How to calculate the number of permutations and combinations if k is equal to n? What kind of ships would an amphibious species build? Who is the "young student" André Weil is referring to in his letter from the prison? Why can't modern fighter aircraft shoot down second world war bombers? =80640. Since you are choosing from the bride or the groom, the answer is, One person from bride and groom can be selected by 2c1 way. Why does the wording of how many ways can a photographer 6 people from a group of 10 ask for permutations and not combinations?

Kenneth Rosen's Discrete Mathematics 6th Edition, Creating new Help Center documents for Review queues: Project overview. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy.

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Asking for help, clarification, or responding to other answers. The bride and the groom are the priority so they should be the most prominent. For part (c), one way to count the permutations is. It only takes a minute to sign up. However, this is just combinations, and not permutations to my understanding, because there are 6 ways to arrange either the bride or groom for each such combination. In how many ways can these people be arranged for a photograph? b) both the bride and groom must be in the picture? Use MathJax to format equations. By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service. Is there a name for paths that follow gridlines? The chapter where that is introduced comes much later. I am looking back in my work and this is how I did it. However, part c) is incredibly confusing because the answers I have found seem to just use combinations, and not permutations. If we were considering permutations, would it not need to be $[6 * 40320] + [6 * 40320] = 483,840$ permutations? there is no restriction about their position so can be arranged 6! Therefore I would not have access to that knowledge directly. Oh I see now. The same reasoning is used to solve b) (permutations again), which comes to $1 \times 1 \times 8 \times 7 \times 6 \times 5 = 1,680$ combinations times $6 * 5$ ways to permute each combination, so the answer is $30 * 1680 = 50,400$. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. a row from a group of 10 people where the bride and groom are part of the group of 10 such that (a) at least one of them (the bride and the groom) must be in the pic? Course Hero is not sponsored or endorsed by any college or university. To learn more, see our tips on writing great answers. How easy is it to recognize that a creature is under the Dominate Monster spell? Bride and groom take two places each of 1 way. Two people to the …

Answer = 2c1 * 8c5 * 6! Making statements based on opinion; back them up with references or personal experience. Thus, there are $80640=(2\cdot6)\cdot8\cdot7\cdot6\cdot5\cdot4$ permutations in this case. How many ways can a photographer at a wedding arrange 6 people in. As you noted, "arrange ... in a row" indicates that order does matter, i.e., we are counting permutations. Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. This sort of makes sense.

But the number of permutations is actually $6 \times 15120 = 90720$, since for each combination the bride has 6 possible positions. c) exactly one of the bride and the groom is in the picture? 366,926 students got unstuck by Course Hero in the last week, Our Expert Tutors provide step by step solutions to help you excel in your courses. Terraforming Mars using a combination of aerogel and GM microbes? What wording of the question says I am looking for permutations and not combinations? Different ways of arranging a group of 10 people. In how many ways can 4 people occupy 10 chairs in a row if no two sit on adjacent chairs. In how many ways may 8 people form a circle for a folk dance? Variations: in how many ways can people be arranged, What is the main difference between a decoder and a demultiplexer. Discrete Mathematics and Its Applications | 6th Edition, Discrete Mathematics and Its Applications, 9780072880083, 9780073107790, 9780073312712. $8\cdot7\cdot6\cdot5\cdot4=6720$ ways to choose and arrange the other five people. $2$ ways to choose exactly one of the bride and groom. A photographer can arrange 6 people in a row from a group of 10 people in many ways. How can election winners of states be confirmed, although the remaining uncounted votes are more than the difference in votes? For example, to solve part a), I calculated all the (unique) combinations of 6 people from a group of 10 where 1 is always the bride. MathJax reference. Should I speak up for her? The placement of this problem in the book doesn't make complete sense. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Jenn Air Grill Costco, The White Cat That Swore Vengeance Chapter 43, Jon Favreau Emily Black, Pheasant For Sale, Fenty Beauty Dupes, Floor Jack Big Wheel Kit, Lil Uzi Vert Gfriend Tattoo, Toca Madera Chicago, How Do You Remove The Drip Pan From A Frigidaire Refrigerator, Jump Math Worksheets Grade 4, Joseph Melville See, Citrix Backstage Login, Used Super Pocket Bike, Mcpi Spawn Entity, My Idea Of Paradise Essay, Oculus Rift Headset Cable, Chris Webber House, Tiktok Hairstyle Boy, Is The Examined Life The Best Path To The Good Life Essay, Ir Conjugaison Espagnol, Naïm Signification Biblique, How Tall Is Sodapoppin, Role Of Top Management In Setting Organizational Direction, " /> How to calculate the number of permutations and combinations if k is equal to n? What kind of ships would an amphibious species build? Who is the "young student" André Weil is referring to in his letter from the prison? Why can't modern fighter aircraft shoot down second world war bombers? =80640. Since you are choosing from the bride or the groom, the answer is, One person from bride and groom can be selected by 2c1 way. Why does the wording of how many ways can a photographer 6 people from a group of 10 ask for permutations and not combinations?

Kenneth Rosen's Discrete Mathematics 6th Edition, Creating new Help Center documents for Review queues: Project overview. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy.

how to append public keys to remote host instead of copy it, Suggestions for braking with severe osteoarthritis in both hands.

Asking for help, clarification, or responding to other answers. The bride and the groom are the priority so they should be the most prominent. For part (c), one way to count the permutations is. It only takes a minute to sign up. However, this is just combinations, and not permutations to my understanding, because there are 6 ways to arrange either the bride or groom for each such combination. In how many ways can these people be arranged for a photograph? b) both the bride and groom must be in the picture? Use MathJax to format equations. By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service. Is there a name for paths that follow gridlines? The chapter where that is introduced comes much later. I am looking back in my work and this is how I did it. However, part c) is incredibly confusing because the answers I have found seem to just use combinations, and not permutations. If we were considering permutations, would it not need to be $[6 * 40320] + [6 * 40320] = 483,840$ permutations? there is no restriction about their position so can be arranged 6! Therefore I would not have access to that knowledge directly. Oh I see now. The same reasoning is used to solve b) (permutations again), which comes to $1 \times 1 \times 8 \times 7 \times 6 \times 5 = 1,680$ combinations times $6 * 5$ ways to permute each combination, so the answer is $30 * 1680 = 50,400$. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. a row from a group of 10 people where the bride and groom are part of the group of 10 such that (a) at least one of them (the bride and the groom) must be in the pic? Course Hero is not sponsored or endorsed by any college or university. To learn more, see our tips on writing great answers. How easy is it to recognize that a creature is under the Dominate Monster spell? Bride and groom take two places each of 1 way. Two people to the …

Answer = 2c1 * 8c5 * 6! Making statements based on opinion; back them up with references or personal experience. Thus, there are $80640=(2\cdot6)\cdot8\cdot7\cdot6\cdot5\cdot4$ permutations in this case. How many ways can a photographer at a wedding arrange 6 people in. As you noted, "arrange ... in a row" indicates that order does matter, i.e., we are counting permutations. Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. This sort of makes sense.

But the number of permutations is actually $6 \times 15120 = 90720$, since for each combination the bride has 6 possible positions. c) exactly one of the bride and the groom is in the picture? 366,926 students got unstuck by Course Hero in the last week, Our Expert Tutors provide step by step solutions to help you excel in your courses. Terraforming Mars using a combination of aerogel and GM microbes? What wording of the question says I am looking for permutations and not combinations? Different ways of arranging a group of 10 people. In how many ways can 4 people occupy 10 chairs in a row if no two sit on adjacent chairs. In how many ways may 8 people form a circle for a folk dance? Variations: in how many ways can people be arranged, What is the main difference between a decoder and a demultiplexer. Discrete Mathematics and Its Applications | 6th Edition, Discrete Mathematics and Its Applications, 9780072880083, 9780073107790, 9780073312712. $8\cdot7\cdot6\cdot5\cdot4=6720$ ways to choose and arrange the other five people. $2$ ways to choose exactly one of the bride and groom. A photographer can arrange 6 people in a row from a group of 10 people in many ways. How can election winners of states be confirmed, although the remaining uncounted votes are more than the difference in votes? For example, to solve part a), I calculated all the (unique) combinations of 6 people from a group of 10 where 1 is always the bride. MathJax reference. Should I speak up for her? The placement of this problem in the book doesn't make complete sense. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Jenn Air Grill Costco, The White Cat That Swore Vengeance Chapter 43, Jon Favreau Emily Black, Pheasant For Sale, Fenty Beauty Dupes, Floor Jack Big Wheel Kit, Lil Uzi Vert Gfriend Tattoo, Toca Madera Chicago, How Do You Remove The Drip Pan From A Frigidaire Refrigerator, Jump Math Worksheets Grade 4, Joseph Melville See, Citrix Backstage Login, Used Super Pocket Bike, Mcpi Spawn Entity, My Idea Of Paradise Essay, Oculus Rift Headset Cable, Chris Webber House, Tiktok Hairstyle Boy, Is The Examined Life The Best Path To The Good Life Essay, Ir Conjugaison Espagnol, Naïm Signification Biblique, How Tall Is Sodapoppin, Role Of Top Management In Setting Organizational Direction, " /> in how many ways can a photographer at a wedding arrange 6
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in how many ways can a photographer at a wedding arrange 6

  • November 6, 2020

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